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134331444641 is a prime number
BaseRepresentation
bin111110100011011000…
…1110010110110100001
3110211201210022102122102
41331012301302312201
54200102322212031
6141413325020145
712463600303562
oct1750661626641
9424653272572
10134331444641
1151a73664649
122204b3b4655
13c88a383724
14670485a169
1537632597cb
hex1f46c72da1

134331444641 has 2 divisors, whose sum is σ = 134331444642. Its totient is φ = 134331444640.

The previous prime is 134331444613. The next prime is 134331444661. The reversal of 134331444641 is 146444133431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126110214400 + 8221230241 = 355120^2 + 90671^2 .

It is an emirp because it is prime and its reverse (146444133431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134331444641 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134331444595 and 134331444604.

It is not a weakly prime, because it can be changed into another prime (134331444661) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67165722320 + 67165722321.

It is an arithmetic number, because the mean of its divisors is an integer number (67165722321).

Almost surely, 2134331444641 is an apocalyptic number.

It is an amenable number.

134331444641 is a deficient number, since it is larger than the sum of its proper divisors (1).

134331444641 is an equidigital number, since it uses as much as digits as its factorization.

134331444641 is an evil number, because the sum of its binary digits is even.

The product of its digits is 165888, while the sum is 38.

The spelling of 134331444641 in words is "one hundred thirty-four billion, three hundred thirty-one million, four hundred forty-four thousand, six hundred forty-one".