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134333054202343 is a prime number
BaseRepresentation
bin11110100010110011011001…
…111110100011000111100111
3122121122010002111221110210111
4132202303121332203013213
5120101403043333433333
61153411430403233451
740203146211551143
oct3642633176430747
9577563074843714
10134333054202343
1139891368050597
1213096790078887
1359c5725255c19
142525a7c560223
15107e49ea3a4cd
hex7a2cd9fa31e7

134333054202343 has 2 divisors, whose sum is σ = 134333054202344. Its totient is φ = 134333054202342.

The previous prime is 134333054202307. The next prime is 134333054202377. The reversal of 134333054202343 is 343202450333431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134333054202343 - 241 = 132134030946791 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134333054202296 and 134333054202305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134333054202643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67166527101171 + 67166527101172.

It is an arithmetic number, because the mean of its divisors is an integer number (67166527101172).

Almost surely, 2134333054202343 is an apocalyptic number.

134333054202343 is a deficient number, since it is larger than the sum of its proper divisors (1).

134333054202343 is an equidigital number, since it uses as much as digits as its factorization.

134333054202343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 933120, while the sum is 40.

The spelling of 134333054202343 in words is "one hundred thirty-four trillion, three hundred thirty-three billion, fifty-four million, two hundred two thousand, three hundred forty-three".