Base | Representation |
---|---|
bin | 11110100010110011011001… |
… | …111110100011000111100111 |
3 | 122121122010002111221110210111 |
4 | 132202303121332203013213 |
5 | 120101403043333433333 |
6 | 1153411430403233451 |
7 | 40203146211551143 |
oct | 3642633176430747 |
9 | 577563074843714 |
10 | 134333054202343 |
11 | 39891368050597 |
12 | 13096790078887 |
13 | 59c5725255c19 |
14 | 2525a7c560223 |
15 | 107e49ea3a4cd |
hex | 7a2cd9fa31e7 |
134333054202343 has 2 divisors, whose sum is σ = 134333054202344. Its totient is φ = 134333054202342.
The previous prime is 134333054202307. The next prime is 134333054202377. The reversal of 134333054202343 is 343202450333431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134333054202343 - 241 = 132134030946791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134333054202296 and 134333054202305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134333054202643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67166527101171 + 67166527101172.
It is an arithmetic number, because the mean of its divisors is an integer number (67166527101172).
Almost surely, 2134333054202343 is an apocalyptic number.
134333054202343 is a deficient number, since it is larger than the sum of its proper divisors (1).
134333054202343 is an equidigital number, since it uses as much as digits as its factorization.
134333054202343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 933120, while the sum is 40.
The spelling of 134333054202343 in words is "one hundred thirty-four trillion, three hundred thirty-three billion, fifty-four million, two hundred two thousand, three hundred forty-three".
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