Base | Representation |
---|---|
bin | 111110100011011100… |
… | …1010101001011000111 |
3 | 110211201221000210122102 |
4 | 1331012321111023013 |
5 | 4200103323421411 |
6 | 141413435222315 |
7 | 12463623142403 |
oct | 1750671251307 |
9 | 424657023572 |
10 | 134333420231 |
11 | 51a7479396a |
12 | 2204bba799b |
13 | c88a8c5a0a |
14 | 6704c12103 |
15 | 37634e9d3b |
hex | 1f46e552c7 |
134333420231 has 2 divisors, whose sum is σ = 134333420232. Its totient is φ = 134333420230.
The previous prime is 134333420173. The next prime is 134333420251. The reversal of 134333420231 is 132024333431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134333420231 - 26 = 134333420167 is a prime.
It is a super-2 number, since 2×1343334202312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134333420194 and 134333420203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134333420251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67166710115 + 67166710116.
It is an arithmetic number, because the mean of its divisors is an integer number (67166710116).
Almost surely, 2134333420231 is an apocalyptic number.
134333420231 is a deficient number, since it is larger than the sum of its proper divisors (1).
134333420231 is an equidigital number, since it uses as much as digits as its factorization.
134333420231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 134333420231 its reverse (132024333431), we get a palindrome (266357753662).
The spelling of 134333420231 in words is "one hundred thirty-four billion, three hundred thirty-three million, four hundred twenty thousand, two hundred thirty-one".
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