Base | Representation |
---|---|
bin | 10011100011000101100… |
… | …111011101010100101111 |
3 | 11202102102001002101021012 |
4 | 103203011213131110233 |
5 | 134002132341023011 |
6 | 2505042502455435 |
7 | 166024230144365 |
oct | 23430547352457 |
9 | 4672361071235 |
10 | 1343345251631 |
11 | 4787894122a9 |
12 | 19842373457b |
13 | 998a5244026 |
14 | 49038151635 |
15 | 24e2444ca8b |
hex | 138c59dd52f |
1343345251631 has 2 divisors, whose sum is σ = 1343345251632. Its totient is φ = 1343345251630.
The previous prime is 1343345251607. The next prime is 1343345251637. The reversal of 1343345251631 is 1361525433431.
It is a strong prime.
It is an emirp because it is prime and its reverse (1361525433431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1343345251631 - 222 = 1343341057327 is a prime.
It is a super-2 number, since 2×13433452516312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343345251637) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671672625815 + 671672625816.
It is an arithmetic number, because the mean of its divisors is an integer number (671672625816).
Almost surely, 21343345251631 is an apocalyptic number.
1343345251631 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343345251631 is an equidigital number, since it uses as much as digits as its factorization.
1343345251631 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 388800, while the sum is 41.
The spelling of 1343345251631 in words is "one trillion, three hundred forty-three billion, three hundred forty-five million, two hundred fifty-one thousand, six hundred thirty-one".
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