Base | Representation |
---|---|
bin | 101000000010001… |
… | …1110010100010111 |
3 | 10110121202020211011 |
4 | 1100010132110113 |
5 | 10222344200124 |
6 | 341144353051 |
7 | 45201200263 |
oct | 12004362427 |
9 | 3417666734 |
10 | 1343350039 |
11 | 62a316849 |
12 | 315a75787 |
13 | 1854055a5 |
14 | ca5a70a3 |
15 | 7ce04994 |
hex | 5011e517 |
1343350039 has 2 divisors, whose sum is σ = 1343350040. Its totient is φ = 1343350038.
The previous prime is 1343349859. The next prime is 1343350123. The reversal of 1343350039 is 9300533431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1343350039 - 211 = 1343347991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1343350639) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671675019 + 671675020.
It is an arithmetic number, because the mean of its divisors is an integer number (671675020).
Almost surely, 21343350039 is an apocalyptic number.
1343350039 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343350039 is an equidigital number, since it uses as much as digits as its factorization.
1343350039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 31.
The square root of 1343350039 is about 36651.7399177720. The cubic root of 1343350039 is about 1103.3917457252.
The spelling of 1343350039 in words is "one billion, three hundred forty-three million, three hundred fifty thousand, thirty-nine".
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