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13433597389 is a prime number
BaseRepresentation
bin11001000001011010…
…00110110111001101
31021200012200110021001
430200231012313031
5210003000104024
610101000340301
7653616456652
oct144055066715
937605613231
1013433597389
115773a08603
12272aa74691
1313611777c4
14916197c29
15539550244
hex320b46dcd

13433597389 has 2 divisors, whose sum is σ = 13433597390. Its totient is φ = 13433597388.

The previous prime is 13433597357. The next prime is 13433597407. The reversal of 13433597389 is 98379533431.

13433597389 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11774420100 + 1659177289 = 108510^2 + 40733^2 .

It is an emirp because it is prime and its reverse (98379533431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13433597389 - 25 = 13433597357 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13433597329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6716798694 + 6716798695.

It is an arithmetic number, because the mean of its divisors is an integer number (6716798695).

Almost surely, 213433597389 is an apocalyptic number.

It is an amenable number.

13433597389 is a deficient number, since it is larger than the sum of its proper divisors (1).

13433597389 is an equidigital number, since it uses as much as digits as its factorization.

13433597389 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7348320, while the sum is 55.

The spelling of 13433597389 in words is "thirteen billion, four hundred thirty-three million, five hundred ninety-seven thousand, three hundred eighty-nine".