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134342309632339 is a prime number
BaseRepresentation
bin11110100010111100000001…
…101001001101100101010011
3122121122222222112200000220001
4132202330001221031211103
5120102031022231213324
61153420001031230431
740203624445451104
oct3642740151154523
9577588875600801
10134342309632339
1139895287544096
1213098533818417
1359c656b8ca313
1425262b98663ab
15107e84236ee44
hex7a2f01a4d953

134342309632339 has 2 divisors, whose sum is σ = 134342309632340. Its totient is φ = 134342309632338.

The previous prime is 134342309632117. The next prime is 134342309632361. The reversal of 134342309632339 is 933236903243431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134342309632339 - 213 = 134342309624147 is a prime.

It is a super-2 number, since 2×1343423096323392 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 134342309632339.

It is not a weakly prime, because it can be changed into another prime (134342309632379) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67171154816169 + 67171154816170.

It is an arithmetic number, because the mean of its divisors is an integer number (67171154816170).

Almost surely, 2134342309632339 is an apocalyptic number.

134342309632339 is a deficient number, since it is larger than the sum of its proper divisors (1).

134342309632339 is an equidigital number, since it uses as much as digits as its factorization.

134342309632339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22674816, while the sum is 55.

The spelling of 134342309632339 in words is "one hundred thirty-four trillion, three hundred forty-two billion, three hundred nine million, six hundred thirty-two thousand, three hundred thirty-nine".