134343313104000 has 2048 divisors, whose sum is σ = 599048458444800. Its totient is φ = 25720823808000.

The previous prime is 134343313103941. The next prime is 134343313104017. The reversal of 134343313104000 is 401313343431.

134343313104000 is digitally balanced in base 8, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×134343313104000² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 29741709742 + ... + 29741714258.

It is an arithmetic number, because the mean of its divisors is an integer number (292504130100).

Almost surely, 2^{134343313104000} is an apocalyptic number.

134343313104000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134343313104000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (299524229222400).

134343313104000 is an abundant number, since it is smaller than the sum of its proper divisors (464705145340800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134343313104000 is a wasteful number, since it uses less digits than its factorization.

134343313104000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5199 (or 5177 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 30.

Adding to 134343313104000 its reverse (401313343431), we get a palindrome (134744626447431).

The spelling of 134343313104000 in words is "one hundred thirty-four trillion, three hundred forty-three billion, three hundred thirteen million, one hundred four thousand".