Base | Representation |
---|---|
bin | 1100001101111111001100… |
… | …0011001101100111111001 |
3 | 1202120022122020211112121202 |
4 | 3003133303003031213321 |
5 | 3230102213223042223 |
6 | 44323410254543545 |
7 | 2554414646410364 |
oct | 303376303154771 |
9 | 52508566745552 |
10 | 13434440440313 |
11 | 430a572436702 |
12 | 160b826b07bb5 |
13 | 765b29610909 |
14 | 3463322770db |
15 | 1846d9930428 |
hex | c37f30cd9f9 |
13434440440313 has 2 divisors, whose sum is σ = 13434440440314. Its totient is φ = 13434440440312.
The previous prime is 13434440440279. The next prime is 13434440440321. The reversal of 13434440440313 is 31304404443431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13419598378729 + 14842061584 = 3663277^2 + 121828^2 .
It is a cyclic number.
It is not a de Polignac number, because 13434440440313 - 212 = 13434440436217 is a prime.
It is not a weakly prime, because it can be changed into another prime (13434440400313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717220220156 + 6717220220157.
It is an arithmetic number, because the mean of its divisors is an integer number (6717220220157).
Almost surely, 213434440440313 is an apocalyptic number.
It is an amenable number.
13434440440313 is a deficient number, since it is larger than the sum of its proper divisors (1).
13434440440313 is an equidigital number, since it uses as much as digits as its factorization.
13434440440313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 331776, while the sum is 38.
Adding to 13434440440313 its reverse (31304404443431), we get a palindrome (44738844883744).
The spelling of 13434440440313 in words is "thirteen trillion, four hundred thirty-four billion, four hundred forty million, four hundred forty thousand, three hundred thirteen".
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