Base | Representation |
---|---|
bin | 10011100011001011111… |
… | …010111001110000011101 |
3 | 11202102200102002120101112 |
4 | 103203023322321300131 |
5 | 134002341424342000 |
6 | 2505101201351405 |
7 | 166026653121125 |
oct | 23431372716035 |
9 | 4672612076345 |
10 | 1343451012125 |
11 | 478833088772 |
12 | 198453038565 |
13 | 998c11237c1 |
14 | 49048201c85 |
15 | 24e2d88e235 |
hex | 138cbeb9c1d |
1343451012125 has 32 divisors (see below), whose sum is σ = 1779297062400. Its totient is φ = 1009234694400.
The previous prime is 1343451012107. The next prime is 1343451012149. The reversal of 1343451012125 is 5212101543431.
It is not a de Polignac number, because 1343451012125 - 214 = 1343450995741 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1343451012091 and 1343451012100.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 212816 + ... + 1652934.
It is an arithmetic number, because the mean of its divisors is an integer number (55603033200).
Almost surely, 21343451012125 is an apocalyptic number.
It is an amenable number.
1343451012125 is a deficient number, since it is larger than the sum of its proper divisors (435846050275).
1343451012125 is a wasteful number, since it uses less digits than its factorization.
1343451012125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1440590 (or 1440580 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 1343451012125 its reverse (5212101543431), we get a palindrome (6555552555556).
The spelling of 1343451012125 in words is "one trillion, three hundred forty-three billion, four hundred fifty-one million, twelve thousand, one hundred twenty-five".
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