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1343503150433 is a prime number
BaseRepresentation
bin10011100011001111000…
…001110010110101100001
311202102211001012110200222
4103203033001302311201
5134002443301303213
62505110303052425
7166031155232633
oct23431701626541
94672731173628
101343503150433
1147885a559a84
121984685a1115
13998cbb7a282
14490510d4a53
1524e3323c808
hex138cf072d61

1343503150433 has 2 divisors, whose sum is σ = 1343503150434. Its totient is φ = 1343503150432.

The previous prime is 1343503150391. The next prime is 1343503150453. The reversal of 1343503150433 is 3340513053431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 679028737024 + 664474413409 = 824032^2 + 815153^2 .

It is a cyclic number.

It is not a de Polignac number, because 1343503150433 - 26 = 1343503150369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1343503150393 and 1343503150402.

It is not a weakly prime, because it can be changed into another prime (1343503150453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671751575216 + 671751575217.

It is an arithmetic number, because the mean of its divisors is an integer number (671751575217).

Almost surely, 21343503150433 is an apocalyptic number.

It is an amenable number.

1343503150433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343503150433 is an equidigital number, since it uses as much as digits as its factorization.

1343503150433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 35.

The spelling of 1343503150433 in words is "one trillion, three hundred forty-three billion, five hundred three million, one hundred fifty thousand, four hundred thirty-three".