1343542320137 has 2 divisors, whose sum is σ = 1343542320138. Its totient is φ = 1343542320136.

The previous prime is 1343542320103. The next prime is 1343542320173. The reversal of 1343542320137 is 7310232453431.

Together with next prime (1343542320173) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1332879486016 + 10662834121 = 1154504^2 + 103261^2 .

It is a cyclic number.

It is not a de Polignac number, because 1343542320137 - 2⁶ = 1343542320073 is a prime.

It is a super-2 number, since 2×1343542320137² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1343542320137.

It is not a weakly prime, because it can be changed into another prime (1343542320437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671771160068 + 671771160069.

It is an arithmetic number, because the mean of its divisors is an integer number (671771160069).

Almost surely, 2^{1343542320137} is an apocalyptic number.

It is an amenable number.

1343542320137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343542320137 is an equidigital number, since it uses as much as digits as its factorization.

1343542320137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 38.

Adding to 1343542320137 its reverse (7310232453431), we get a palindrome (8653774773568).

The spelling of 1343542320137 in words is "one trillion, three hundred forty-three billion, five hundred forty-two million, three hundred twenty thousand, one hundred thirty-seven".