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134365656325501 is a prime number
BaseRepresentation
bin11110100011010001110001…
…001101110001110101111101
3122121202020020121120221002101
4132203101301031301311331
5120102421331004404001
61153434421432025101
740205412136202656
oct3643216115616575
9577666217527071
10134365656325501
11398a41780aa227
12130a0b6a532191
1359c881c755463
14252749240052d
15108025bd13a01
hex7a3471371d7d

134365656325501 has 2 divisors, whose sum is σ = 134365656325502. Its totient is φ = 134365656325500.

The previous prime is 134365656325403. The next prime is 134365656325553. The reversal of 134365656325501 is 105523656563431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106921783409401 + 27443872916100 = 10340299^2 + 5238690^2 .

It is a cyclic number.

It is not a de Polignac number, because 134365656325501 - 223 = 134365647936893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134365656325001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67182828162750 + 67182828162751.

It is an arithmetic number, because the mean of its divisors is an integer number (67182828162751).

Almost surely, 2134365656325501 is an apocalyptic number.

It is an amenable number.

134365656325501 is a deficient number, since it is larger than the sum of its proper divisors (1).

134365656325501 is an equidigital number, since it uses as much as digits as its factorization.

134365656325501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 29160000, while the sum is 55.

The spelling of 134365656325501 in words is "one hundred thirty-four trillion, three hundred sixty-five billion, six hundred fifty-six million, three hundred twenty-five thousand, five hundred one".