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13440042403993 is a prime number
BaseRepresentation
bin1100001110010100000011…
…1101000000100010011001
31202120212002122220210010001
43003211000331000202121
53230200201323411433
644330134212253001
72555003531333122
oct303450075004231
952525078823101
1013440042403993
114311987612957
12161092b011161
137665100a4b1a
14346704273049
1518491664157d
hexc3940f40899

13440042403993 has 2 divisors, whose sum is σ = 13440042403994. Its totient is φ = 13440042403992.

The previous prime is 13440042403981. The next prime is 13440042404011. The reversal of 13440042403993 is 39930424004431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11378397283344 + 2061645120649 = 3373188^2 + 1435843^2 .

It is a cyclic number.

It is not a de Polignac number, because 13440042403993 - 221 = 13440040306841 is a prime.

It is a super-2 number, since 2×134400424039932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13440042403973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720021201996 + 6720021201997.

It is an arithmetic number, because the mean of its divisors is an integer number (6720021201997).

Almost surely, 213440042403993 is an apocalyptic number.

It is an amenable number.

13440042403993 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440042403993 is an equidigital number, since it uses as much as digits as its factorization.

13440042403993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1119744, while the sum is 46.

The spelling of 13440042403993 in words is "thirteen trillion, four hundred forty billion, forty-two million, four hundred three thousand, nine hundred ninety-three".