13440042404011 has 2 divisors, whose sum is σ = 13440042404012. Its totient is φ = 13440042404010.

The previous prime is 13440042403993. The next prime is 13440042404029. The reversal of 13440042404011 is 11040424004431.

It is a balanced prime because it is at equal distance from previous prime (13440042403993) and next prime (13440042404029).

It is a cyclic number.

It is not a de Polignac number, because 13440042404011 - 2⁷ = 13440042403883 is a prime.

It is a super-2 number, since 2×13440042404011² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13440042404051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720021202005 + 6720021202006.

It is an arithmetic number, because the mean of its divisors is an integer number (6720021202006).

Almost surely, 2^{13440042404011} is an apocalyptic number.

13440042404011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440042404011 is an equidigital number, since it uses as much as digits as its factorization.

13440042404011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 13440042404011 its reverse (11040424004431), we get a palindrome (24480466408442).

The spelling of 13440042404011 in words is "thirteen trillion, four hundred forty billion, forty-two million, four hundred four thousand, eleven".