Base | Representation |
---|---|
bin | 11110100011110010010101… |
… | …010111011001010010111111 |
3 | 122121212120111110201220200211 |
4 | 132203302111113121102333 |
5 | 120104004433334031133 |
6 | 1153502443231533251 |
7 | 40211060501264566 |
oct | 3643622527312277 |
9 | 577776443656624 |
10 | 134400622564543 |
11 | 39907a90691145 |
12 | 130a78a868a227 |
13 | 59cbc0298832a |
14 | 252904c23cbdd |
15 | 1081106925bcd |
hex | 7a3c955d94bf |
134400622564543 has 2 divisors, whose sum is σ = 134400622564544. Its totient is φ = 134400622564542.
The previous prime is 134400622564529. The next prime is 134400622564553. The reversal of 134400622564543 is 345465226004431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134400622564543 - 217 = 134400622433471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134400622564553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200311282271 + 67200311282272.
It is an arithmetic number, because the mean of its divisors is an integer number (67200311282272).
Almost surely, 2134400622564543 is an apocalyptic number.
134400622564543 is a deficient number, since it is larger than the sum of its proper divisors (1).
134400622564543 is an equidigital number, since it uses as much as digits as its factorization.
134400622564543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8294400, while the sum is 49.
Adding to 134400622564543 its reverse (345465226004431), we get a palindrome (479865848568974).
The spelling of 134400622564543 in words is "one hundred thirty-four trillion, four hundred billion, six hundred twenty-two million, five hundred sixty-four thousand, five hundred forty-three".
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