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134401040013 = 344800346671
BaseRepresentation
bin111110100101011101…
…1010001111010001101
3110211220122021020112210
41331022323101322031
54200223131240023
6141424252421033
712465403663542
oct1751273217215
9424818236483
10134401040013
1151aa9979689
122206a777779
13c89b910016
14670dbb4bc9
153769405593
hex1f4aed1e8d

134401040013 has 4 divisors (see below), whose sum is σ = 179201386688. Its totient is φ = 89600693340.

The previous prime is 134401039967. The next prime is 134401040041. The reversal of 134401040013 is 310040104431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 134401040013 - 28 = 134401039757 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134401040083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22400173333 + ... + 22400173338.

It is an arithmetic number, because the mean of its divisors is an integer number (44800346672).

Almost surely, 2134401040013 is an apocalyptic number.

It is an amenable number.

134401040013 is a deficient number, since it is larger than the sum of its proper divisors (44800346675).

134401040013 is an equidigital number, since it uses as much as digits as its factorization.

134401040013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44800346674.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 134401040013 its reverse (310040104431), we get a palindrome (444441144444).

The spelling of 134401040013 in words is "one hundred thirty-four billion, four hundred one million, forty thousand, thirteen".

Divisors: 1 3 44800346671 134401040013