Base | Representation |
---|---|
bin | 111110100101011101… |
… | …1010001111001011111 |
3 | 110211220122021020111002 |
4 | 1331022323101321133 |
5 | 4200223131234332 |
6 | 141424252420515 |
7 | 12465403663445 |
oct | 1751273217137 |
9 | 424818236432 |
10 | 134401039967 |
11 | 51aa9979647 |
12 | 2206a77773b |
13 | c89b90ccac |
14 | 670dbb4b95 |
15 | 3769405562 |
hex | 1f4aed1e5f |
134401039967 has 2 divisors, whose sum is σ = 134401039968. Its totient is φ = 134401039966.
The previous prime is 134401039961. The next prime is 134401040041. The reversal of 134401039967 is 769930104431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134401039967 - 28 = 134401039711 is a prime.
It is a super-2 number, since 2×1344010399672 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134401039961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200519983 + 67200519984.
It is an arithmetic number, because the mean of its divisors is an integer number (67200519984).
Almost surely, 2134401039967 is an apocalyptic number.
134401039967 is a deficient number, since it is larger than the sum of its proper divisors (1).
134401039967 is an equidigital number, since it uses as much as digits as its factorization.
134401039967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 489888, while the sum is 47.
The spelling of 134401039967 in words is "one hundred thirty-four billion, four hundred one million, thirty-nine thousand, nine hundred sixty-seven".
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