134401040041 has 2 divisors, whose sum is σ = 134401040042. Its totient is φ = 134401040040.

The previous prime is 134401039967. The next prime is 134401040057. The reversal of 134401040041 is 140040104431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121449462016 + 12951578025 = 348496^2 + 113805^2 .

It is an emirp because it is prime and its reverse (140040104431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134401040041 - 2²¹ = 134398942889 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134401039994 and 134401040021.

It is not a weakly prime, because it can be changed into another prime (134401040141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200520020 + 67200520021.

It is an arithmetic number, because the mean of its divisors is an integer number (67200520021).

Almost surely, 2^134401040041 is an apocalyptic number.

It is an amenable number.

134401040041 is a deficient number, since it is larger than the sum of its proper divisors (1).

134401040041 is an equidigital number, since it uses as much as digits as its factorization.

134401040041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 134401040041 its reverse (140040104431), we get a palindrome (274441144472).

The spelling of 134401040041 in words is "one hundred thirty-four billion, four hundred one million, forty thousand, forty-one".