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134401040035 = 531186431537
BaseRepresentation
bin111110100101011101…
…1010001111010100011
3110211220122021020120121
41331022323101322203
54200223131240120
6141424252421111
712465403663603
oct1751273217243
9424818236517
10134401040035
1151aa99796a9
122206a777797
13c89b910032
14670dbb4c03
1537694055aa
hex1f4aed1ea3

134401040035 has 8 divisors (see below), whose sum is σ = 161799839136. Its totient is φ = 107175104640.

The previous prime is 134401039967. The next prime is 134401040041. The reversal of 134401040035 is 530040104431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-134401040035 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134401039991 and 134401040009.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43214214 + ... + 43217323.

It is an arithmetic number, because the mean of its divisors is an integer number (20224979892).

Almost surely, 2134401040035 is an apocalyptic number.

134401040035 is a deficient number, since it is larger than the sum of its proper divisors (27398799101).

134401040035 is an equidigital number, since it uses as much as digits as its factorization.

134401040035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86431853.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 134401040035 its reverse (530040104431), we get a palindrome (664441144466).

The spelling of 134401040035 in words is "one hundred thirty-four billion, four hundred one million, forty thousand, thirty-five".

Divisors: 1 5 311 1555 86431537 432157685 26880208007 134401040035