134401104343442 has 4 divisors (see below), whose sum is σ = 201601656515166. Its totient is φ = 67200552171720.

The previous prime is 134401104343393. The next prime is 134401104343447. The reversal of 134401104343442 is 244343401104431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 110304207661561 + 24096896681881 = 10502581^2 + 4908859^2 .

It is a junction number, because it is equal to n+sod(n) for n = 134401104343396 and 134401104343405.

It is not an unprimeable number, because it can be changed into a prime (134401104343447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33600276085859 + ... + 33600276085862.

Almost surely, 2^{134401104343442} is an apocalyptic number.

134401104343442 is a deficient number, since it is larger than the sum of its proper divisors (67200552171724).

134401104343442 is an equidigital number, since it uses as much as digits as its factorization.

134401104343442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67200552171723.

The product of its (nonzero) digits is 221184, while the sum is 38.

Adding to 134401104343442 its reverse (244343401104431), we get a palindrome (378744505447873).

The spelling of 134401104343442 in words is "one hundred thirty-four trillion, four hundred one billion, one hundred four million, three hundred forty-three thousand, four hundred forty-two".