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134401104350069 is a prime number
BaseRepresentation
bin11110100011110010110010…
…000101010000101101110101
3122121212121202001022011012012
4132203302302011100231311
5120104011430203200234
61153503003122134005
740211105441350244
oct3643626205205565
9577777661264165
10134401104350069
11399082086377a7
12130a7a01ab1305
1359cbc7b73391b
14252909621295b
151081133d920ce
hex7a3cb2150b75

134401104350069 has 2 divisors, whose sum is σ = 134401104350070. Its totient is φ = 134401104350068.

The previous prime is 134401104350063. The next prime is 134401104350099. The reversal of 134401104350069 is 960053401104431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124374464428900 + 10026639921169 = 11152330^2 + 3166487^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134401104350069 is a prime.

It is a super-2 number, since 2×1344011043500692 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134401104350063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200552175034 + 67200552175035.

It is an arithmetic number, because the mean of its divisors is an integer number (67200552175035).

Almost surely, 2134401104350069 is an apocalyptic number.

It is an amenable number.

134401104350069 is a deficient number, since it is larger than the sum of its proper divisors (1).

134401104350069 is an equidigital number, since it uses as much as digits as its factorization.

134401104350069 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 134401104350069 in words is "one hundred thirty-four trillion, four hundred one billion, one hundred four million, three hundred fifty thousand, sixty-nine".