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134401104433 is a prime number
BaseRepresentation
bin111110100101011101…
…1100001101000110001
3110211220122101111220201
41331022323201220301
54200223140320213
6141424254035201
712465404352421
oct1751273415061
9424818344821
10134401104433
1151aa9a13022
122206a7a8b01
13c89b93343b
14670dbd0481
1537694196dd
hex1f4aee1a31

134401104433 has 2 divisors, whose sum is σ = 134401104434. Its totient is φ = 134401104432.

The previous prime is 134401104419. The next prime is 134401104443. The reversal of 134401104433 is 334401104431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99361757089 + 35039347344 = 315217^2 + 187188^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134401104433 is a prime.

It is not a weakly prime, because it can be changed into another prime (134401104443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200552216 + 67200552217.

It is an arithmetic number, because the mean of its divisors is an integer number (67200552217).

Almost surely, 2134401104433 is an apocalyptic number.

It is an amenable number.

134401104433 is a deficient number, since it is larger than the sum of its proper divisors (1).

134401104433 is an equidigital number, since it uses as much as digits as its factorization.

134401104433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 134401104433 its reverse (334401104431), we get a palindrome (468802208864).

The spelling of 134401104433 in words is "one hundred thirty-four billion, four hundred one million, one hundred four thousand, four hundred thirty-three".