13440115131231 has 4 divisors (see below), whose sum is σ = 17920153508312. Its totient is φ = 8960076754152.

The previous prime is 13440115131227. The next prime is 13440115131251. The reversal of 13440115131231 is 13213151104431.

It is a happy number.

13440115131231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13440115131231 - 2² = 13440115131227 is a prime.

It is a super-3 number, since 3×13440115131231³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13440115131211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2240019188536 + ... + 2240019188541.

It is an arithmetic number, because the mean of its divisors is an integer number (4480038377078).

Almost surely, 2^{13440115131231} is an apocalyptic number.

13440115131231 is a deficient number, since it is larger than the sum of its proper divisors (4480038377081).

13440115131231 is an equidigital number, since it uses as much as digits as its factorization.

13440115131231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4480038377080.

The product of its (nonzero) digits is 4320, while the sum is 30.

Adding to 13440115131231 its reverse (13213151104431), we get a palindrome (26653266235662).

The spelling of 13440115131231 in words is "thirteen trillion, four hundred forty billion, one hundred fifteen million, one hundred thirty-one thousand, two hundred thirty-one".