134402103131 has 2 divisors, whose sum is σ = 134402103132. Its totient is φ = 134402103130.

The previous prime is 134402103127. The next prime is 134402103133. The reversal of 134402103131 is 131301204431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134402103131 - 2² = 134402103127 is a prime.

It is a super-2 number, since 2×134402103131² (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 134402103133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 134402103097 and 134402103106.

It is not a weakly prime, because it can be changed into another prime (134402103133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67201051565 + 67201051566.

It is an arithmetic number, because the mean of its divisors is an integer number (67201051566).

Almost surely, 2^134402103131 is an apocalyptic number.

134402103131 is a deficient number, since it is larger than the sum of its proper divisors (1).

134402103131 is an equidigital number, since it uses as much as digits as its factorization.

134402103131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 134402103131 its reverse (131301204431), we get a palindrome (265703307562).

The spelling of 134402103131 in words is "one hundred thirty-four billion, four hundred two million, one hundred three thousand, one hundred thirty-one".