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1344032681 is a prime number
BaseRepresentation
bin101000000011100…
…0100111110101001
310110200000221020012
41100013010332221
510223033021211
6341211141305
745210042425
oct12007047651
93420027205
101344032681
1162a742712
12316144835
131855b4214
14ca703b85
157cedbd8b
hex501c4fa9

1344032681 has 2 divisors, whose sum is σ = 1344032682. Its totient is φ = 1344032680.

The previous prime is 1344032629. The next prime is 1344032689. The reversal of 1344032681 is 1862304431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 691690000 + 652342681 = 26300^2 + 25541^2 .

It is a cyclic number.

It is not a de Polignac number, because 1344032681 - 26 = 1344032617 is a prime.

It is a super-2 number, since 2×13440326812 = 3612847695192095522, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1344032689) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672016340 + 672016341.

It is an arithmetic number, because the mean of its divisors is an integer number (672016341).

Almost surely, 21344032681 is an apocalyptic number.

It is an amenable number.

1344032681 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344032681 is an equidigital number, since it uses as much as digits as its factorization.

1344032681 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 32.

The square root of 1344032681 is about 36661.0512806166. The cubic root of 1344032681 is about 1103.5786153610.

The spelling of 1344032681 in words is "one billion, three hundred forty-four million, thirty-two thousand, six hundred eighty-one".