1344034331131 has 2 divisors, whose sum is σ = 1344034331132. Its totient is φ = 1344034331130.

The previous prime is 1344034331113. The next prime is 1344034331137. The reversal of 1344034331131 is 1311334304431.

It is a happy number.

Together with previous prime (1344034331113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (1311334304431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1344034331131 - 2²⁷ = 1343900113403 is a prime.

It is a super-2 number, since 2×1344034331131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1344034331093 and 1344034331102.

It is not a weakly prime, because it can be changed into another prime (1344034331137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672017165565 + 672017165566.

It is an arithmetic number, because the mean of its divisors is an integer number (672017165566).

Almost surely, 2^{1344034331131} is an apocalyptic number.

1344034331131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344034331131 is an equidigital number, since it uses as much as digits as its factorization.

1344034331131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 1344034331131 its reverse (1311334304431), we get a palindrome (2655368635562).

The spelling of 1344034331131 in words is "one trillion, three hundred forty-four billion, thirty-four million, three hundred thirty-one thousand, one hundred thirty-one".