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134404123201 is a prime number
BaseRepresentation
bin111110100101100011…
…1000010101001000001
3110211220212001212212221
41331023013002221001
54200224423420301
6141424442451041
712465442124455
oct1751307025101
9424825055787
10134404123201
1152000695077
122206b803a81
13c89c44c4aa
146710378665
153769813da1
hex1f4b1c2a41

134404123201 has 2 divisors, whose sum is σ = 134404123202. Its totient is φ = 134404123200.

The previous prime is 134404123151. The next prime is 134404123327. The reversal of 134404123201 is 102321404431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98028479025 + 36375644176 = 313095^2 + 190724^2 .

It is a cyclic number.

It is not a de Polignac number, because 134404123201 - 213 = 134404115009 is a prime.

It is not a weakly prime, because it can be changed into another prime (134404423201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67202061600 + 67202061601.

It is an arithmetic number, because the mean of its divisors is an integer number (67202061601).

Almost surely, 2134404123201 is an apocalyptic number.

It is an amenable number.

134404123201 is a deficient number, since it is larger than the sum of its proper divisors (1).

134404123201 is an equidigital number, since it uses as much as digits as its factorization.

134404123201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 134404123201 its reverse (102321404431), we get a palindrome (236725527632).

The spelling of 134404123201 in words is "one hundred thirty-four billion, four hundred four million, one hundred twenty-three thousand, two hundred one".