13440541125132 has 72 divisors (see below), whose sum is σ = 37197113243472. Its totient is φ = 4058187638400.

The previous prime is 13440541125131. The next prime is 13440541125133. The reversal of 13440541125132 is 23152114504431.

13440541125132 is a `hidden beast` number, since 1 + 3 + 4 + 405 + 4 + 112 + 5 + 132 = 666.

It is an interprime number because it is at equal distance from previous prime (13440541125131) and next prime (13440541125133).

It is a Harshad number since it is a multiple of its sum of digits (36).

It is not an unprimeable number, because it can be changed into a prime (13440541125131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 61155219 + ... + 61374602.

It is an arithmetic number, because the mean of its divisors is an integer number (516626572826).

Almost surely, 2^{13440541125132} is an apocalyptic number.

13440541125132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13440541125132 is an abundant number, since it is smaller than the sum of its proper divisors (23756572118340).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13440541125132 is a wasteful number, since it uses less digits than its factorization.

13440541125132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 122530119 (or 122530114 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 36.

Adding to 13440541125132 its reverse (23152114504431), we get a palindrome (36592655629563).

The spelling of 13440541125132 in words is "thirteen trillion, four hundred forty billion, five hundred forty-one million, one hundred twenty-five thousand, one hundred thirty-two".