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13440550531 is a prime number
BaseRepresentation
bin11001000010001111…
…01000011010000011
31021200200202201011211
430201013220122003
5210011240104111
610101405350551
7654032536342
oct144107503203
937620681154
1013440550531
115777927601
122731268457
1313627405a5
14917087b59
15539e75521
hex3211e8683

13440550531 has 2 divisors, whose sum is σ = 13440550532. Its totient is φ = 13440550530.

The previous prime is 13440550499. The next prime is 13440550547. The reversal of 13440550531 is 13505504431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13440550531 - 25 = 13440550499 is a prime.

It is a super-2 number, since 2×134405505312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13440550493 and 13440550502.

It is not a weakly prime, because it can be changed into another prime (13440550561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720275265 + 6720275266.

It is an arithmetic number, because the mean of its divisors is an integer number (6720275266).

Almost surely, 213440550531 is an apocalyptic number.

13440550531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13440550531 is an equidigital number, since it uses as much as digits as its factorization.

13440550531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 31.

The spelling of 13440550531 in words is "thirteen billion, four hundred forty million, five hundred fifty thousand, five hundred thirty-one".