Base | Representation |
---|---|
bin | 111110100101101001… |
… | …0111000000100001001 |
3 | 110211221001220111120221 |
4 | 1331023102320010021 |
5 | 4200231222204414 |
6 | 141425033150041 |
7 | 12465510365416 |
oct | 1751322700411 |
9 | 424831814527 |
10 | 134407225609 |
11 | 52002413a48 |
12 | 2207085b321 |
13 | c89cc97637 |
14 | 671094510d |
15 | 3769c28224 |
hex | 1f4b4b8109 |
134407225609 has 2 divisors, whose sum is σ = 134407225610. Its totient is φ = 134407225608.
The previous prime is 134407225607. The next prime is 134407225643. The reversal of 134407225609 is 906522704431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 129453881209 + 4953344400 = 359797^2 + 70380^2 .
It is a cyclic number.
It is not a de Polignac number, because 134407225609 - 21 = 134407225607 is a prime.
Together with 134407225607, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (134407225607) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67203612804 + 67203612805.
It is an arithmetic number, because the mean of its divisors is an integer number (67203612805).
Almost surely, 2134407225609 is an apocalyptic number.
It is an amenable number.
134407225609 is a deficient number, since it is larger than the sum of its proper divisors (1).
134407225609 is an equidigital number, since it uses as much as digits as its factorization.
134407225609 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 43.
The spelling of 134407225609 in words is "one hundred thirty-four billion, four hundred seven million, two hundred twenty-five thousand, six hundred nine".
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