13441121340511 has 4 divisors (see below), whose sum is σ = 13442289840352. Its totient is φ = 13439952840672.

The previous prime is 13441121340433. The next prime is 13441121340523. The reversal of 13441121340511 is 11504312114431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13441121340511 is a prime.

It is a super-2 number, since 2×13441121340511² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13441121340611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 584232666 + ... + 584255671.

It is an arithmetic number, because the mean of its divisors is an integer number (3360572460088).

Almost surely, 2^{13441121340511} is an apocalyptic number.

13441121340511 is a deficient number, since it is larger than the sum of its proper divisors (1168499841).

13441121340511 is a wasteful number, since it uses less digits than its factorization.

13441121340511 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1168499840.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 13441121340511 its reverse (11504312114431), we get a palindrome (24945433454942).

The spelling of 13441121340511 in words is "thirteen trillion, four hundred forty-one billion, one hundred twenty-one million, three hundred forty thousand, five hundred eleven".