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13441121340433 is a prime number
BaseRepresentation
bin1100001110011000000101…
…0000110100110000010001
31202120221212212010102122221
43003212001100310300101
53230204404030343213
644330433233501041
72555042342210323
oct303460120646021
952527785112587
1013441121340433
114312390650866
121610b90411781
1376665278c257
143467a768b613
1518497b21638d
hexc3981434c11

13441121340433 has 2 divisors, whose sum is σ = 13441121340434. Its totient is φ = 13441121340432.

The previous prime is 13441121340421. The next prime is 13441121340523. The reversal of 13441121340433 is 33404312114431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13344613568784 + 96507771649 = 3653028^2 + 310657^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13441121340433 is a prime.

It is not a weakly prime, because it can be changed into another prime (13441121340133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720560670216 + 6720560670217.

It is an arithmetic number, because the mean of its divisors is an integer number (6720560670217).

Almost surely, 213441121340433 is an apocalyptic number.

It is an amenable number.

13441121340433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13441121340433 is an equidigital number, since it uses as much as digits as its factorization.

13441121340433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 13441121340433 its reverse (33404312114431), we get a palindrome (46845433454864).

The spelling of 13441121340433 in words is "thirteen trillion, four hundred forty-one billion, one hundred twenty-one million, three hundred forty thousand, four hundred thirty-three".