Base | Representation |
---|---|
bin | 1100001110011000000101… |
… | …0000110100110001101011 |
3 | 1202120221212212010102210021 |
4 | 3003212001100310301223 |
5 | 3230204404030344043 |
6 | 44330433233501311 |
7 | 2555042342210512 |
oct | 303460120646153 |
9 | 52527785112707 |
10 | 13441121340523 |
11 | 4312390650938 |
12 | 1610b90411837 |
13 | 76665278c2c6 |
14 | 3467a768b679 |
15 | 18497b2163ed |
hex | c3981434c6b |
13441121340523 has 2 divisors, whose sum is σ = 13441121340524. Its totient is φ = 13441121340522.
The previous prime is 13441121340433. The next prime is 13441121340607. The reversal of 13441121340523 is 32504312114431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13441121340523 is a prime.
It is not a weakly prime, because it can be changed into another prime (13441121340323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720560670261 + 6720560670262.
It is an arithmetic number, because the mean of its divisors is an integer number (6720560670262).
Almost surely, 213441121340523 is an apocalyptic number.
13441121340523 is a deficient number, since it is larger than the sum of its proper divisors (1).
13441121340523 is an equidigital number, since it uses as much as digits as its factorization.
13441121340523 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 13441121340523 its reverse (32504312114431), we get a palindrome (45945433454954).
The spelling of 13441121340523 in words is "thirteen trillion, four hundred forty-one billion, one hundred twenty-one million, three hundred forty thousand, five hundred twenty-three".
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