13441121340521 has 4 divisors (see below), whose sum is σ = 15361281532032. Its totient is φ = 11520961149012.

The previous prime is 13441121340433. The next prime is 13441121340523. The reversal of 13441121340521 is 12504312114431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2^k-13441121340521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13441121340523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 960080095745 + ... + 960080095758.

It is an arithmetic number, because the mean of its divisors is an integer number (3840320383008).

Almost surely, 2^{13441121340521} is an apocalyptic number.

It is an amenable number.

13441121340521 is a deficient number, since it is larger than the sum of its proper divisors (1920160191511).

13441121340521 is an equidigital number, since it uses as much as digits as its factorization.

13441121340521 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1920160191510.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 13441121340521 its reverse (12504312114431), we get a palindrome (25945433454952).

The spelling of 13441121340521 in words is "thirteen trillion, four hundred forty-one billion, one hundred twenty-one million, three hundred forty thousand, five hundred twenty-one".