Base | Representation |
---|---|
bin | 1100001110011000000101… |
… | …0000110100110011100001 |
3 | 1202120221212212010102221122 |
4 | 3003212001100310303201 |
5 | 3230204404030400031 |
6 | 44330433233502025 |
7 | 2555042342211041 |
oct | 303460120646341 |
9 | 52527785112848 |
10 | 13441121340641 |
11 | 4312390650a35 |
12 | 1610b90411915 |
13 | 76665278c387 |
14 | 3467a768b721 |
15 | 18497b21647b |
hex | c3981434ce1 |
13441121340641 has 2 divisors, whose sum is σ = 13441121340642. Its totient is φ = 13441121340640.
The previous prime is 13441121340611. The next prime is 13441121340671. The reversal of 13441121340641 is 14604312114431.
It is a balanced prime because it is at equal distance from previous prime (13441121340611) and next prime (13441121340671).
It can be written as a sum of positive squares in only one way, i.e., 12804381179041 + 636740161600 = 3578321^2 + 797960^2 .
It is a cyclic number.
It is not a de Polignac number, because 13441121340641 - 222 = 13441117146337 is a prime.
It is not a weakly prime, because it can be changed into another prime (13441121340611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720560670320 + 6720560670321.
It is an arithmetic number, because the mean of its divisors is an integer number (6720560670321).
Almost surely, 213441121340641 is an apocalyptic number.
It is an amenable number.
13441121340641 is a deficient number, since it is larger than the sum of its proper divisors (1).
13441121340641 is an equidigital number, since it uses as much as digits as its factorization.
13441121340641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 35.
The spelling of 13441121340641 in words is "thirteen trillion, four hundred forty-one billion, one hundred twenty-one million, three hundred forty thousand, six hundred forty-one".
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