Base | Representation |
---|---|
bin | 10011100011110011011… |
… | …100011010111001000101 |
3 | 11202111101121211102200212 |
4 | 103203303130122321011 |
5 | 134010221203010041 |
6 | 2505251050045205 |
7 | 166052254266134 |
oct | 23436334327105 |
9 | 4674347742625 |
10 | 1344114110021 |
11 | 479043412a61 |
12 | 1985b9119805 |
13 | 99998612417 |
14 | 490ac2d191b |
15 | 24e6bbc28eb |
hex | 138f371ae45 |
1344114110021 has 2 divisors, whose sum is σ = 1344114110022. Its totient is φ = 1344114110020.
The previous prime is 1344114109973. The next prime is 1344114110063. The reversal of 1344114110021 is 1200114114431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1291620885025 + 52493224996 = 1136495^2 + 229114^2 .
It is an emirp because it is prime and its reverse (1200114114431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344114110021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344114110071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672057055010 + 672057055011.
It is an arithmetic number, because the mean of its divisors is an integer number (672057055011).
Almost surely, 21344114110021 is an apocalyptic number.
It is an amenable number.
1344114110021 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344114110021 is an equidigital number, since it uses as much as digits as its factorization.
1344114110021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1344114110021 its reverse (1200114114431), we get a palindrome (2544228224452).
The spelling of 1344114110021 in words is "one trillion, three hundred forty-four billion, one hundred fourteen million, one hundred ten thousand, twenty-one".
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