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13441325054303 = 59227819068717
BaseRepresentation
bin1100001110011000110101…
…1001111011100101011111
31202120222102001110011120002
43003212031121323211133
53230210313203214203
644330505352044515
72555050364563316
oct303461531734537
952528361404502
1013441325054303
114312485640033
12161102869373b
13766685a46ac3
143467c675927d
1518498e055d88
hexc398d67b95f

13441325054303 has 4 divisors (see below), whose sum is σ = 13669144123080. Its totient is φ = 13213505985528.

The previous prime is 13441325054279. The next prime is 13441325054317. The reversal of 13441325054303 is 30345052314431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13441325054303 - 230 = 13440251312479 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13441325050303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113909534300 + ... + 113909534417.

It is an arithmetic number, because the mean of its divisors is an integer number (3417286030770).

Almost surely, 213441325054303 is an apocalyptic number.

13441325054303 is a deficient number, since it is larger than the sum of its proper divisors (227819068777).

13441325054303 is an equidigital number, since it uses as much as digits as its factorization.

13441325054303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 227819068776.

The product of its (nonzero) digits is 259200, while the sum is 38.

Adding to 13441325054303 its reverse (30345052314431), we get a palindrome (43786377368734).

The spelling of 13441325054303 in words is "thirteen trillion, four hundred forty-one billion, three hundred twenty-five million, fifty-four thousand, three hundred three".

Divisors: 1 59 227819068717 13441325054303