Base | Representation |
---|---|
bin | 1100001110011000110101… |
… | …1001111011100101011111 |
3 | 1202120222102001110011120002 |
4 | 3003212031121323211133 |
5 | 3230210313203214203 |
6 | 44330505352044515 |
7 | 2555050364563316 |
oct | 303461531734537 |
9 | 52528361404502 |
10 | 13441325054303 |
11 | 4312485640033 |
12 | 161102869373b |
13 | 766685a46ac3 |
14 | 3467c675927d |
15 | 18498e055d88 |
hex | c398d67b95f |
13441325054303 has 4 divisors (see below), whose sum is σ = 13669144123080. Its totient is φ = 13213505985528.
The previous prime is 13441325054279. The next prime is 13441325054317. The reversal of 13441325054303 is 30345052314431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13441325054303 - 230 = 13440251312479 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13441325050303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113909534300 + ... + 113909534417.
It is an arithmetic number, because the mean of its divisors is an integer number (3417286030770).
Almost surely, 213441325054303 is an apocalyptic number.
13441325054303 is a deficient number, since it is larger than the sum of its proper divisors (227819068777).
13441325054303 is an equidigital number, since it uses as much as digits as its factorization.
13441325054303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 227819068776.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 13441325054303 its reverse (30345052314431), we get a palindrome (43786377368734).
The spelling of 13441325054303 in words is "thirteen trillion, four hundred forty-one billion, three hundred twenty-five million, fifty-four thousand, three hundred three".
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