Base | Representation |
---|---|
bin | 1100001110011000110101… |
… | …1001111011100101101101 |
3 | 1202120222102001110011120121 |
4 | 3003212031121323211231 |
5 | 3230210313203214232 |
6 | 44330505352044541 |
7 | 2555050364563336 |
oct | 303461531734555 |
9 | 52528361404517 |
10 | 13441325054317 |
11 | 4312485640046 |
12 | 1611028693751 |
13 | 766685a46b04 |
14 | 3467c675928d |
15 | 18498e055d97 |
hex | c398d67b96d |
13441325054317 has 2 divisors, whose sum is σ = 13441325054318. Its totient is φ = 13441325054316.
The previous prime is 13441325054279. The next prime is 13441325054321. The reversal of 13441325054317 is 71345052314431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7011342635236 + 6429982419081 = 2647894^2 + 2535741^2 .
It is a cyclic number.
It is not a de Polignac number, because 13441325054317 - 211 = 13441325052269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13441325054357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720662527158 + 6720662527159.
It is an arithmetic number, because the mean of its divisors is an integer number (6720662527159).
Almost surely, 213441325054317 is an apocalyptic number.
It is an amenable number.
13441325054317 is a deficient number, since it is larger than the sum of its proper divisors (1).
13441325054317 is an equidigital number, since it uses as much as digits as its factorization.
13441325054317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 604800, while the sum is 43.
Adding to 13441325054317 its reverse (71345052314431), we get a palindrome (84786377368748).
The spelling of 13441325054317 in words is "thirteen trillion, four hundred forty-one billion, three hundred twenty-five million, fifty-four thousand, three hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •