13441402334011 has 2 divisors, whose sum is σ = 13441402334012. Its totient is φ = 13441402334010.

The previous prime is 13441402333999. The next prime is 13441402334023. The reversal of 13441402334011 is 11043320414431.

It is a balanced prime because it is at equal distance from previous prime (13441402333999) and next prime (13441402334023).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13441402334011 is a prime.

It is not a weakly prime, because it can be changed into another prime (13441402134011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720701167005 + 6720701167006.

It is an arithmetic number, because the mean of its divisors is an integer number (6720701167006).

Almost surely, 2^{13441402334011} is an apocalyptic number.

13441402334011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13441402334011 is an equidigital number, since it uses as much as digits as its factorization.

13441402334011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13441402334011 its reverse (11043320414431), we get a palindrome (24484722748442).

The spelling of 13441402334011 in words is "thirteen trillion, four hundred forty-one billion, four hundred two million, three hundred thirty-four thousand, eleven".