Base | Representation |
---|---|
bin | 111110100101111010… |
… | …0100001110100001101 |
3 | 110211221200111200202221 |
4 | 1331023310201310031 |
5 | 4200241002003443 |
6 | 141425550215341 |
7 | 12465645360016 |
oct | 1751364416415 |
9 | 424850450687 |
10 | 134416047373 |
11 | 52007399963 |
12 | 220737b4551 |
13 | c8a1a65b0a |
14 | 6711ba000d |
15 | 376a8bbeed |
hex | 1f4bd21d0d |
134416047373 has 2 divisors, whose sum is σ = 134416047374. Its totient is φ = 134416047372.
The previous prime is 134416047329. The next prime is 134416047397. The reversal of 134416047373 is 373740614431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131157692649 + 3258354724 = 362157^2 + 57082^2 .
It is a cyclic number.
It is not a de Polignac number, because 134416047373 - 213 = 134416039181 is a prime.
It is a super-2 number, since 2×1344160473732 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134416048373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67208023686 + 67208023687.
It is an arithmetic number, because the mean of its divisors is an integer number (67208023687).
Almost surely, 2134416047373 is an apocalyptic number.
It is an amenable number.
134416047373 is a deficient number, since it is larger than the sum of its proper divisors (1).
134416047373 is an equidigital number, since it uses as much as digits as its factorization.
134416047373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 508032, while the sum is 43.
The spelling of 134416047373 in words is "one hundred thirty-four billion, four hundred sixteen million, forty-seven thousand, three hundred seventy-three".
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