Base | Representation |
---|---|
bin | 1100001110011011010111… |
… | …0101101101100011100111 |
3 | 1202121001011022220222220122 |
4 | 3003212311311231203213 |
5 | 3230213210334104021 |
6 | 44331100543552155 |
7 | 2555103242623043 |
oct | 303466565554347 |
9 | 52531138828818 |
10 | 13442003425511 |
11 | 43127a35573a1 |
12 | 16111978bb65b |
13 | 76676345259b |
14 | 34684c8a3023 |
15 | 1849cd8a4bab |
hex | c39b5d6d8e7 |
13442003425511 has 2 divisors, whose sum is σ = 13442003425512. Its totient is φ = 13442003425510.
The previous prime is 13442003425507. The next prime is 13442003425531. The reversal of 13442003425511 is 11552430024431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13442003425511 - 22 = 13442003425507 is a prime.
It is a super-2 number, since 2×134420034255112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13442003425531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721001712755 + 6721001712756.
It is an arithmetic number, because the mean of its divisors is an integer number (6721001712756).
Almost surely, 213442003425511 is an apocalyptic number.
13442003425511 is a deficient number, since it is larger than the sum of its proper divisors (1).
13442003425511 is an equidigital number, since it uses as much as digits as its factorization.
13442003425511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 13442003425511 its reverse (11552430024431), we get a palindrome (24994433449942).
The spelling of 13442003425511 in words is "thirteen trillion, four hundred forty-two billion, three million, four hundred twenty-five thousand, five hundred eleven".
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