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13442003425511 is a prime number
BaseRepresentation
bin1100001110011011010111…
…0101101101100011100111
31202121001011022220222220122
43003212311311231203213
53230213210334104021
644331100543552155
72555103242623043
oct303466565554347
952531138828818
1013442003425511
1143127a35573a1
1216111978bb65b
1376676345259b
1434684c8a3023
151849cd8a4bab
hexc39b5d6d8e7

13442003425511 has 2 divisors, whose sum is σ = 13442003425512. Its totient is φ = 13442003425510.

The previous prime is 13442003425507. The next prime is 13442003425531. The reversal of 13442003425511 is 11552430024431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13442003425511 - 22 = 13442003425507 is a prime.

It is a super-2 number, since 2×134420034255112 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13442003425531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721001712755 + 6721001712756.

It is an arithmetic number, because the mean of its divisors is an integer number (6721001712756).

Almost surely, 213442003425511 is an apocalyptic number.

13442003425511 is a deficient number, since it is larger than the sum of its proper divisors (1).

13442003425511 is an equidigital number, since it uses as much as digits as its factorization.

13442003425511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 13442003425511 its reverse (11552430024431), we get a palindrome (24994433449942).

The spelling of 13442003425511 in words is "thirteen trillion, four hundred forty-two billion, three million, four hundred twenty-five thousand, five hundred eleven".