Base | Representation |
---|---|
bin | 11001000010011011… |
… | …00011110001110001 |
3 | 1021200210200122201202 |
4 | 30201031203301301 |
5 | 210012134320213 |
6 | 10101502540545 |
7 | 654052000562 |
oct | 144115436161 |
9 | 37623618652 |
10 | 13442104433 |
11 | 577879901a |
12 | 2731897755 |
13 | 1362b65964 |
14 | 917370169 |
15 | 53a180b58 |
hex | 321363c71 |
13442104433 has 2 divisors, whose sum is σ = 13442104434. Its totient is φ = 13442104432.
The previous prime is 13442104349. The next prime is 13442104453. The reversal of 13442104433 is 33440124431.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11208880384 + 2233224049 = 105872^2 + 47257^2 .
It is a cyclic number.
It is not a de Polignac number, because 13442104433 - 28 = 13442104177 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13442104396 and 13442104405.
It is not a weakly prime, because it can be changed into another prime (13442104453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721052216 + 6721052217.
It is an arithmetic number, because the mean of its divisors is an integer number (6721052217).
Almost surely, 213442104433 is an apocalyptic number.
It is an amenable number.
13442104433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13442104433 is an equidigital number, since it uses as much as digits as its factorization.
13442104433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 13442104433 its reverse (33440124431), we get a palindrome (46882228864).
The spelling of 13442104433 in words is "thirteen billion, four hundred forty-two million, one hundred four thousand, four hundred thirty-three".
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