13442112301 has 2 divisors, whose sum is σ = 13442112302. Its totient is φ = 13442112300.

The previous prime is 13442112293. The next prime is 13442112319. The reversal of 13442112301 is 10321124431.

13442112301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7639634025 + 5802478276 = 87405^2 + 76174^2 .

It is an emirp because it is prime and its reverse (10321124431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13442112301 - 2³ = 13442112293 is a prime.

It is a super-2 number, since 2×13442112301² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13442112601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721056150 + 6721056151.

It is an arithmetic number, because the mean of its divisors is an integer number (6721056151).

Almost surely, 2^13442112301 is an apocalyptic number.

It is an amenable number.

13442112301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13442112301 is an equidigital number, since it uses as much as digits as its factorization.

13442112301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 13442112301 its reverse (10321124431), we get a palindrome (23763236732).

The spelling of 13442112301 in words is "thirteen billion, four hundred forty-two million, one hundred twelve thousand, three hundred one".