13442314013437 has 2 divisors, whose sum is σ = 13442314013438. Its totient is φ = 13442314013436.

The previous prime is 13442314013411. The next prime is 13442314013467. The reversal of 13442314013437 is 73431041324431.

13442314013437 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13359127340196 + 83186673241 = 3655014^2 + 288421^2 .

It is a cyclic number.

It is not a de Polignac number, because 13442314013437 - 2⁷ = 13442314013309 is a prime.

It is a super-3 number, since 3×13442314013437³ (a number of 40 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13442314013437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13442314013467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721157006718 + 6721157006719.

It is an arithmetic number, because the mean of its divisors is an integer number (6721157006719).

Almost surely, 2^{13442314013437} is an apocalyptic number.

It is an amenable number.

13442314013437 is a deficient number, since it is larger than the sum of its proper divisors (1).

13442314013437 is an equidigital number, since it uses as much as digits as its factorization.

13442314013437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 290304, while the sum is 40.

Adding to 13442314013437 its reverse (73431041324431), we get a palindrome (86873355337868).

The spelling of 13442314013437 in words is "thirteen trillion, four hundred forty-two billion, three hundred fourteen million, thirteen thousand, four hundred thirty-seven".