Base | Representation |
---|---|
bin | 1100001110011100100101… |
… | …1001000010111000101111 |
3 | 1202121002000012011121210211 |
4 | 3003213021121002320233 |
5 | 3230214343323030043 |
6 | 44331153302443251 |
7 | 2555114335053232 |
oct | 303471131027057 |
9 | 52532005147724 |
10 | 13442331455023 |
11 | 4312951735869 |
12 | 1611269733527 |
13 | 7667b63b54a3 |
14 | 346880291419 |
15 | 1849ec59da9d |
hex | c39c9642e2f |
13442331455023 has 2 divisors, whose sum is σ = 13442331455024. Its totient is φ = 13442331455022.
The previous prime is 13442331454991. The next prime is 13442331455039. The reversal of 13442331455023 is 32055413324431.
13442331455023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13442331455023 - 25 = 13442331454991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13442331455083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721165727511 + 6721165727512.
It is an arithmetic number, because the mean of its divisors is an integer number (6721165727512).
Almost surely, 213442331455023 is an apocalyptic number.
13442331455023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13442331455023 is an equidigital number, since it uses as much as digits as its factorization.
13442331455023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 13442331455023 its reverse (32055413324431), we get a palindrome (45497744779454).
The spelling of 13442331455023 in words is "thirteen trillion, four hundred forty-two billion, three hundred thirty-one million, four hundred fifty-five thousand, twenty-three".
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