Base | Representation |
---|---|
bin | 11001000010011101… |
… | …01011111100101111 |
3 | 1021200211020200020102 |
4 | 30201032223330233 |
5 | 210012223300142 |
6 | 10101513141315 |
7 | 654054341456 |
oct | 144116537457 |
9 | 37624220212 |
10 | 13442400047 |
11 | 577898012a |
12 | 27319ba83b |
13 | 1362c3a38b |
14 | 917409b9d |
15 | 53a1dd532 |
hex | 3213abf2f |
13442400047 has 2 divisors, whose sum is σ = 13442400048. Its totient is φ = 13442400046.
The previous prime is 13442400043. The next prime is 13442400137. The reversal of 13442400047 is 74000424431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13442400047 - 22 = 13442400043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13442399992 and 13442400019.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13442400043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6721200023 + 6721200024.
It is an arithmetic number, because the mean of its divisors is an integer number (6721200024).
Almost surely, 213442400047 is an apocalyptic number.
13442400047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13442400047 is an equidigital number, since it uses as much as digits as its factorization.
13442400047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 29.
Adding to 13442400047 its reverse (74000424431), we get a palindrome (87442824478).
The spelling of 13442400047 in words is "thirteen billion, four hundred forty-two million, four hundred thousand, forty-seven".
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