Base | Representation |
---|---|
bin | 11110100100001000101101… |
… | …110011010000011110010011 |
3 | 122121221212112022201002101201 |
4 | 132210020231303100132103 |
5 | 120104403143114413442 |
6 | 1153521500043012031 |
7 | 40212601155256654 |
oct | 3644105563203623 |
9 | 577855468632351 |
10 | 134424654841747 |
11 | 399171a323a766 |
12 | 130b0494b0a017 |
13 | 5a01262875cba |
14 | 252a28bc7b52b |
15 | 1081a616907b7 |
hex | 7a422dcd0793 |
134424654841747 has 2 divisors, whose sum is σ = 134424654841748. Its totient is φ = 134424654841746.
The previous prime is 134424654841739. The next prime is 134424654841819. The reversal of 134424654841747 is 747148456424431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134424654841747 - 23 = 134424654841739 is a prime.
It is a super-2 number, since 2×1344246548417472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134424654841727) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67212327420873 + 67212327420874.
It is an arithmetic number, because the mean of its divisors is an integer number (67212327420874).
Almost surely, 2134424654841747 is an apocalyptic number.
134424654841747 is a deficient number, since it is larger than the sum of its proper divisors (1).
134424654841747 is an equidigital number, since it uses as much as digits as its factorization.
134424654841747 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 289013760, while the sum is 64.
The spelling of 134424654841747 in words is "one hundred thirty-four trillion, four hundred twenty-four billion, six hundred fifty-four million, eight hundred forty-one thousand, seven hundred forty-seven".
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