Base | Representation |
---|---|
bin | 10011100011111011110… |
… | …101111010110110101111 |
3 | 11202111202102222000020201 |
4 | 103203323311322312233 |
5 | 134011013240343041 |
6 | 2505313042054331 |
7 | 166055615034643 |
oct | 23437365726657 |
9 | 4674672860221 |
10 | 1344255012271 |
11 | 479105a009a6 |
12 | 19863834a3a7 |
13 | 999bb877332 |
14 | 490c2cccc23 |
15 | 24e79256631 |
hex | 138fbd7adaf |
1344255012271 has 2 divisors, whose sum is σ = 1344255012272. Its totient is φ = 1344255012270.
The previous prime is 1344255012173. The next prime is 1344255012293. The reversal of 1344255012271 is 1722105524431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1344255012271 - 215 = 1344254979503 is a prime.
It is a super-4 number, since 4×13442550122714 (a number of 50 digits) contains 4444 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1344255012271.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1344255072271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672127506135 + 672127506136.
It is an arithmetic number, because the mean of its divisors is an integer number (672127506136).
Almost surely, 21344255012271 is an apocalyptic number.
1344255012271 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344255012271 is an equidigital number, since it uses as much as digits as its factorization.
1344255012271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 67200, while the sum is 37.
The spelling of 1344255012271 in words is "one trillion, three hundred forty-four billion, two hundred fifty-five million, twelve thousand, two hundred seventy-one".
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