Base | Representation |
---|---|
bin | 11110100100001010011001… |
… | …100101001110011010110011 |
3 | 122121222001012100021021000111 |
4 | 132210022121211032122303 |
5 | 120104420344023241033 |
6 | 1153522355320202151 |
7 | 40212664033241425 |
oct | 3644123145163263 |
9 | 577861170237014 |
10 | 134426463102643 |
11 | 39917a40a26958 |
12 | 130b08ba609357 |
13 | 5a0149039916a |
14 | 252a3c00a4815 |
15 | 1081b1a2cb7cd |
hex | 7a429994e6b3 |
134426463102643 has 2 divisors, whose sum is σ = 134426463102644. Its totient is φ = 134426463102642.
The previous prime is 134426463102641. The next prime is 134426463102647. The reversal of 134426463102643 is 346201364624431.
It is a weak prime.
It is an emirp because it is prime and its reverse (346201364624431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134426463102643 - 21 = 134426463102641 is a prime.
Together with 134426463102641, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (134426463102641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67213231551321 + 67213231551322.
It is an arithmetic number, because the mean of its divisors is an integer number (67213231551322).
Almost surely, 2134426463102643 is an apocalyptic number.
134426463102643 is a deficient number, since it is larger than the sum of its proper divisors (1).
134426463102643 is an equidigital number, since it uses as much as digits as its factorization.
134426463102643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5971968, while the sum is 49.
The spelling of 134426463102643 in words is "one hundred thirty-four trillion, four hundred twenty-six billion, four hundred sixty-three million, one hundred two thousand, six hundred forty-three".
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